Kinematics Question 118
A man goes 10m towards North, then 20m towards East, then displacement is [KCET 1999; JIPMER 1999; AFMC 2003]
Options:
A) 22.5m
25m
C) 25.5m
30m
Show Answer
Answer:
Correct Answer: A
Solution:
$ \vec{r}=20\hat{i}+10\hat{j} $    
$ \therefore \  $
$ r=\sqrt{20^{2}+10^{2}}=22.36 $ m
 BETA
  BETA 
             
             
           
           
           
          