Kinematics Question 333
Question: The velocity-time graph of a body is shown in fig. The ratio of average acceleration during the intervals OA and AB is
Options:
A) 1
B) $ \frac{1}{2} $
C) $ \frac{1}{3} $
D) 3
Show Answer
Answer:
Correct Answer: C
Solution:
During OA, acceleration $ =tan30{}^\circ =sm/s^{2} $ During AB, acceleration $ =-tan60{}^\circ $
$ =-\sqrt{3}\text{ m/}{{s}^{2}} $
$ \text{Required ratio = }\frac{1/\sqrt{3}}{\sqrt{3}}=\frac{1}{3} $
BETA
