Kinematics Question 337
Question: The distance time graph of a particle at time makes angles $ 45{}^\circ $ with the time axis. After one second, it makes angle $ 60{}^\circ $ with the time axis.
What is the acceleration of the particle?
Options:
A) $ \sqrt{3}-1 $
B) $ \sqrt{3}+1 $
C) $ \sqrt{3} $
D) 1
Show Answer
Answer:
Correct Answer: A
Solution:
Velocity at time t is $ tan45{}^\circ =1 $ .
Velocity at time $ ( t=1 ) $ is $ tan60{}^\circ =\sqrt{3} $ .
acceleration is change in velocity in one second = $ \sqrt{3}-1. $
BETA
