Kinematics Question 355
The velocity-time graph of the motion of the body is as shown below. The total distance travelled by the body during the motion is equal to __.
Options:
A) $ \frac{1}{2}( \text{AD+BE} )\times\text{ OC} $
B) $ \frac{1}{2}( \text{OA+BC} )\times\text{ OC} $
C) $ \frac{1}{2}( \text{OC+AB} )\times\text{ AD} $
D) $ \frac{1}{2}( \text{OA+AB} )\times\text{ BC} $
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Answer:
Correct Answer: C
Solution:
distance travelled = area $ \square OABC $
$ =\frac{1}{2}\times ( \text{OC+AB} )\times AD $
BETA
