Kinematics Question 356
Question: Stopping distance of a moving vehicle it’s directly proportional to
Options:
A) square of the initial velocity
B) square of the initial acceleration
C) the initial velocity
D) the initial acceleration
Show Answer
Answer:
Correct Answer: A
Solution:
Let s be the distance travelled by the vehicle before it stops. Final velocity $ v=0 $ , initial velocity = u Using equation of motion $ v^{2}-{{u}^{2}}\text{= 2aS} $
$ 0^{2}-{{u}^{2}}\text{= 2aS} $ Stopping distance, $ \text{S }=-\frac{{{u}^{2}}}{2a} $
BETA
