Kinematics Question 358
Question: The distance travelled by a particle starting from rest and moving with an acceleration $ \frac{4}{3}m{{s}^{-2}} $ , in the third second is:
Options:
A) 6 m
B) 4 m
C) $ \frac{10}{3}m $
D) $ \frac{19}{3}m $
Show Answer
Answer:
Correct Answer: C
Solution:
distance travelled in the nth second is given by $ t _{n}=u+\frac{a}{2}( 2n-1 ) $
$ \text{Put u=0, a=}\frac{4}{3}m{{s}^{-2}}, $
$ n=3 $
$ \therefore d=0+\frac{4}{3\times 2}( 2\times 3-1 )=\frac{4}{6}\times 5=\frac{10}{3}m $
BETA
