Kinematics Question 360
Question: The displacement x of a particle along a straight line at time t is given by: $ \text{x = }{{a} _{0}}\text{+}\frac{{{a} _{1}}t}{2}\text{+}\frac{{{a} _{2}}}{3}{{t}^{2}} $ . The acceleration of the particle is
Options:
A) $ \frac{a _{2}}{3} $
B) $ \frac{2a _{2}}{3} $
C) $ \frac{a _{1}}{2} $
D) $ a _{0}+\frac{a _{2}}{3} $
Show Answer
Answer:
Correct Answer: B
Solution:
$ \frac{dx}{dt}=\frac{a _{t}}{2}+\frac{2a _{2}}{3}\Rightarrow \frac{d^{2}x}{dt}=\frac{2a _{2}}{3} $ Acceleration required
BETA
