Kinematics Question 374
Question: A body starts from rest and it’s uniformly accelerated for 30 s. The distance travelled in the first 10 s it’s $ x _{1} $ , next 10 s it’s $ x _{2} $ , and the last 10 s it’s $ x _{3} $ . Then $ x _{1}:x _{2}:x _{3} $ it’s the same as:
Options:
A) 1:2:4
B) 1:2:5
C) 1:3:5
D) 1:3:9
Show Answer
Answer:
Correct Answer: C
Solution:
$ x _{1}=\frac{1}{2}a{{( 10 )}^{2}}=50a $
$ x _{2}=( 10a )( 10 )+\frac{1}{2}a{{( 10 )}^{2}}=150a $
$ x _{3}=( 20a )( 10 )+\frac{1}{2}a{{( 10 )}^{2}}=250a $
$ \Rightarrow x _{1}:x _{2}:x _{3}::1:3:5 $ s
BETA
