Kinematics Question 39
Question: Two equal forces (P each) act at a point inclined to each other at an angle of 120°. The magnitude of their resultant is [Karnataka CET 2004]
Options:
A) $ P/2 $
B) $ P/4 $
C) $ P $
D) 2P
Show Answer
Answer:
Correct Answer: C
Solution:
$ R=\sqrt{A^{2}+B^{2}+2AB\cos \theta } $
If $ A=B=P $ and $ \theta =120{}^\circ $
then $ R=P $
BETA
