Kinematics Question 393
A man travelling in a car with a maximum speed of 20m/s watches the friend start off at a distance 100m ahead on a motorcycle with constant acceleration ‘a’. The maximum value of ‘a’ for which the man in the car can reach his friend it’s
Options:
A) $ 2m/s^{2} $
B) $ \text{1 }m/s^{2} $
C) $ 4m/s^{2} $
D) $ 8m{{s}^{-2}} $
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Answer:
Correct Answer: A
Solution:
$ v^{2}=u^{2}+2as\text{ 4002a}( 100 );a<2 $
BETA
