Kinematics Question 405
Question: What will be the ratio of the distances moved by a freely falling body from rest on 4th and 5th seconds of journey?
Options:
A) 4 : 5
B) 7 : 9
C) 16 : 25
D) 1 : 1
Show Answer
Answer:
Correct Answer: B
Solution:
$ S _{n}th=u+\frac{a}{2}( 2n-1 ) $
$ \text{So, }\frac{S _{4}}{S _{5}}=\frac{0+\frac{g}{2}( 7 )}{0+\frac{g}{2}( 9 )}=\frac{7}{9} $
BETA
