Kinematics Question 411
Question: A stone is dropped into a well in which the level of water is h below the top of the well. If v it’s velocity of sound, the time T after which the splash it’s heard it’s given by
Options:
A) $ T=2h/v $
B) $ \text{T=}\sqrt{( \frac{2h}{g} )\text{+}\frac{h}{v}} $
C) $ \text{T=}\sqrt{( \frac{2h}{g} )}\text{+}\frac{h}{g} $
D) $ \text{T=}\sqrt{( \frac{h}{2g} )}\text{+}\frac{2h}{v} $
Show Answer
Answer:
Correct Answer: B
Solution:
Time taken by the stone to reach the water level $ t _{1}=\sqrt{\frac{2h}{g}} $
Time taken by sound to come to the mouth of the well, $ t _{2}=\frac{h}{v} $
$ \therefore $
Total time $ t _{1}\text{+}{{t} _{2}}\text{=}\sqrt{\frac{2h}{g}}\text{+}\frac{h}{v} $
BETA
