SATHEE: Kinematics Question 425

Kinematics Question 425

A particle moves along a path ABCD. Then the magnitude of net displacement of the particle from position A to D is:

Options:

A) 10 m

B) $ 5\sqrt{2}m $

C) 9 m

D) $ 7\sqrt{2}m $

Show Answer

Answer:

Correct Answer: D

Solution:

[d] The displacement is $ \sqrt{{{(AF)}^{2}}+{{(FD)}^{2}}}=7\sqrt{2}m $ .

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Kinematics Question 425

A particle moves along a path ABCD. Then the magnitude of net displacement of the particle from position A to D is:

Options:

Answer:

Solution:

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