Kinematics Question 433
Question: At what angle should the two forces 2P and $ \sqrt{2}P $ act so that the resultant force is $ P\sqrt{10}? $
Options:
A) $ 45{}^\circ $
B) $ 60^{o} $
C) $ 90^{o} $
D) $ 120^{o} $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ P\sqrt{10}=\sqrt{4P^{2}+2P^{2}+4\sqrt{2}P^{2}\cos \theta } $
$ \therefore $ $ \theta =45^{o} $
BETA
