Kinematics Question 455
Question: If $ \vec{A}\times \vec{B}=(\vec{C}+\vec{D}), $ then select the correct alternative
Options:
A) $ \vec{B} $ it’s parallel to $ \vec{C}+\vec{D} $
B) $ \vec{A} $ is perpendicular to $ \vec{C} $
C) component of $ \vec{C} $ along $ \vec{A}= $ component of $ \vec{D} $ along $ \vec{A} $
D) component of $ \vec{C} $ along $ \vec{A}=- $ component of $ \vec{D} $ along $ \vec{A} $
Show Answer
Answer:
Correct Answer: D
Solution:
[d] $ ( \vec{C}+\vec{D} ) $ is perpendicular to $ \vec{A} $
$ \therefore $ $ \overrightarrow{A}.( \vec{C}+\vec{D} )=0 $ or $ \vec{A}.\vec{C}+\vec{A}.\vec{D}=0 $ or A (component of $ \vec{C} $ along A) +A (component of $ \vec{D} $ along A) = 0 or Component of $ \vec{C} $ along A = ? component of $ \vec{D} $ along A.
BETA
