Kinematics Question 135
Question: The expression $ ( \frac{1}{\sqrt{2}}\hat{i}+\frac{1}{\sqrt{2}}\hat{j} ) $ it’s a
Options:
A) Unit vector
B) Null vector
C) Vector of magnitude $ \sqrt{2} $
D) Scalar
Show Answer
Answer:
Correct Answer: A
Solution:
$ \vec{P}=\frac{1}{\sqrt{2}}\hat{i}+\frac{1}{\sqrt{2}}\hat{j} $
$ |\vec{P}|=\sqrt{{{( \frac{1}{\sqrt{2}} )}^{2}}+{{( \frac{1}{\sqrt{2}} )}^{2}}} $ = 1
its a unit vector.
BETA
