Kinematics Question 519
Question: A boy projects a stone vertically perpendicular to the trolley car with a speed $ v $ . If the trolley car moves with $ u $ constant velocity m, the time of flight of the stone is:
Options:
A) $ \frac{u+v}{g} $
B) $ \frac{2v}{g} $
C) $ \frac{2u}{g} $
D) none of these
Show Answer
Answer:
Correct Answer: B
Solution:
[b] $ v _{0}\sin \theta =v $
$ v _{0}\cos \theta =u $
Time of flight depends on vertical component of velocity. $ T=\frac{2v _{0}\sin \theta }{g}=\frac{2v}{g} $
BETA
