Kinematics Question 524
A stone is projected from a horizontal plane. It attains maximum height ‘$ H $’ and strikes a stationary smooth wall and falls on the ground vertically below the maximum height. Assuming the collision to be elastic, the height of the point on the wall where ball will strike it is
Options:
A) $ \frac{H}{2} $
B) $ \frac{H}{4} $
C) $ \frac{3H}{4} $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
[c] $ H=\frac{1}{2}g{{(2t)}^{2}}=2gt^{2} $ …(1)
$ h=H-\frac{1}{2}gt^{2} $ …(2)
Solving eqns (1) and (2), we get $ h=H-\frac{H}{4}=\frac{3H}{4} $
BETA
