Kinematics Question 529
Question: A particle is moving on a circular path of radius r with uniform velocity v. The change in velocity when the particle moves from $ P $ to $ Q $ it’s $ (\angle POQ={{40}^{{}^\circ }}) $
Options:
A) $ 2v\cos 40{}^\circ $
B) $ 2v\sin 40{}^\circ $
C) $ 2v\sin 20{}^\circ $
D) $ 2v\cos 20{}^\circ $
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Answer:
Correct Answer: C
Solution:
[c] Change in velocity =$ 2v\sin (\theta /2)=2vsin20{}^\circ $
BETA
