Kinematics Question 569
A body of mass 1 kg is moving in a vertical circular path of radius 1m. The difference between the kinetic energies at its highest and lowest position is
Options:
20J
B)10J
C) $ 4\sqrt{5}J $
D) $ 10( \sqrt{5}-1 )J $
Show Answer
Answer:
Correct Answer: A
Solution:
Difference in kinetic energy = $ 2mgr=2\times 1\times 10\times 1=20J $
BETA
