Kinematics Question 608
If the angles of projection of a projectile with same initial velocity exceed or fall short of $ 45^\circ $ by equal amounts, then the ratio of horizontal ranges is
Options:
A) $ 1:2 $
B)$ 1:3 $
C) $ 1:4 $
D)$ 1:1 $
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Answer:
Correct Answer: D
Solution:
[d] For complementary angles of projection $ (45{}^\circ +\alpha ) $ and $ (45{}^\circ -\alpha ) $ with same initial velocity u, range R it’s same. $ {\theta _{1}}+{\theta _{2}}=( 45{}^\circ +\alpha)+( 45{}^\circ -\alpha)=90{}^\circ $
BETA
