Kinematics Question 15
Question: Let $ \overrightarrow{C}=\overrightarrow{A}+\overrightarrow{B} $ then
Options:
$ |\overrightarrow{C}| $ is always greater than $ |\overrightarrow{A}| $
B) It’s possible to have $ |\overrightarrow{C}|<|\overrightarrow{A}| $ and $ |\overrightarrow{C}|<|\overrightarrow{B}| $
C) c is always equal to A + B
D) c is never equal to A + B
Show Answer
Answer:
Correct Answer: B
Solution:
$ \vec{C}+\vec{A}=\vec{B} $ .
The magnitude of C lies between $ |\vec{A}-\vec{B}| $ and $ |\vec{A}|+|\vec{B}| $ \ $ |\vec{C}|\ <\ |\vec{A}|\ \ and\ \ |\vec{C}|\ <\ |\vec{B}| $
BETA
