Kinematics Question 615
Question: A body projected at an angle with the horizontal has a range 300 m. If the time of flight it’s 6 s, then the horizontal component of velocity is
Options:
A) $ 30\text{ m}{{\text{s}}^{-1}} $
B)$ 50\text{ m}{{\text{s}}^{-1}} $
C) $ 40\text{ m}{{\text{s}}^{-1}} $
D)$ 45\text{ m}{{\text{s}}^{-1}} $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] As we know, $ \text{R = u cos}\theta \times \text{t} $
$ \text{Given, R}\text{=}\text{300}\text{m, t}\text{=}\text{6s} $
$ \therefore \text{u cos}\theta \text{=}\frac{\text{R}}{\text{t}}=\frac{300}{6}=50\text{ m}{{\text{s}}^{-1}} $
BETA
