Kinematics Question 643
A body is thrown horizontally with a velocity $ \sqrt{2gh} $ from the top of a tower of height h. It strikes the level ground through the foot of the tower at a distance x from the tower. The value of x is
Options:
A) $ h $
B)$ h/2 $
C) $ \sim 2,h $
D)$ 2h/3 $
Show Answer
Answer:
Correct Answer: C
Solution:
[c] Using equation to trajectory $ -h=x\tan (0{}^\circ )-\frac{gx^{2}}{2(2gh)({{\cos }^{2}}0{}^\circ )} $
$ \Rightarrow x=2h $
BETA
