Kinematics Question 156
Question: The tension in the horizontal cord it’s 30 N. The weight W and tension in the string OA in Newton are [DPMT 1992]
Options:
A) 30 $ \sqrt{3}, $ 30
B) 30 $ \sqrt{3}, $ 60
C) 60 $ \sqrt{3}, $ 30
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
$ T\sin 30^{o}=30 $ -(i)
$ T\cos 30^{o}=W $ -(ii)
By solving equation (i) and (ii) we get $ W=30\sqrt{3}N $ and $ T=60N $
BETA
