Kinematics Question 695
The greatest height to which a man can throw a stone is $ \sqrt{\frac{2gh}{g}} $ . The greatest distance to which he can throw it, will be
Options:
A) $ 2\pi r^{2}/T $
B) $ \upsilon ,\upsilon \text{ and }\upsilon $
C) $ 2h $
D) $3h$
Show Answer
Answer:
Correct Answer: C
Solution:
[c] For greatest height $ \theta =90^\circ $
$ {H _{\max }}=\frac{u^{2}{{\sin }^{2}}(90{}^\circ )}{2g}=\frac{u^{2}}{2g}=h $
${R _{\max }}=\frac{u^{2}{{\sin }^{2}}(90{}^\circ )}{g}=\frac{u^{2}}{g}=2h $
BETA
