Kinematics Question 706
A particle $ P $ is moving in a circle of radius $ a $ with a uniform speed $ v $. $ C $ is the centre of the circle and $ AB $ is a diameter. When passing through B the angular velocity of $ P $ about $ A $
and $ A $, $ B $, and $ C $ are in the ratio [NCERT 1982]
Options:
A) 1 : 1
B) 1 : 2
C) 2 : 1
D) 4 : 1
Show Answer
Answer:
Correct Answer: B
Solution:
Angular velocity of particle P about point A, $ {\omega _{A}}=\frac{v}{r _{AP}}=\frac{v}{2r} $
Angular velocity of particle P about point C, $ {\omega _{C}}=\frac{v}{r _{PC}}=\frac{v}{r} $
Ratio $ \frac{{\omega _{A}}}{{\omega _{C}}}=\frac{v/2r}{v/r}=\frac{1}{2}. $
BETA
