Kinematics Question 164
Question: A man swimming downstream overcome a float at a point M After travelling distance D he turned back and passed the float at a distance of D/2 from the point M, then the ratio of speed of swimmer with respect to still water to the speed of the river will be
Options:
2
3
4
2.5
Show Answer
Answer:
Correct Answer: B
Solution:
Time taken by man to go from M to P and then P to N = time taken by float to go from M to N. $ \frac{D}{v+u}+\frac{D}{2(v-u)}=\frac{D}{2u} $ Simplify to get $ \frac{v}{u}=3 $
BETA
