Kinematics Question 758
Question: If a particle covers half the circle of radius R with constant speed then[RPMT 2000]
Options:
A) Momentum change is mvr
B) Change in K.E. it’s 1/2 mv²
C) Change in K.E. it’s (1/2)mv²
D) Change in K.E. is zero
Show Answer
Answer:
Correct Answer: D
Solution:
As momentum is vector quantity \ change in momentum $ \Delta P $ = $ 2mv\sin (\theta /2) $ =$ 2mv\sin (90)=2mv $ But kinetic energy remains always constant so change in kinetic energy is zero.
BETA
