Kinematics Question 769
If a cycle wheel of radius 4 m completes one revolution in two seconds. Then acceleration of a point on the cycle wheel will be[Pb. PMT 2001]
Options:
A) $ {{\pi }^{2}}m/s^{2} $
B)$ 2{{\pi }^{2}}m/s^{2} $
C) $ 4{\pi}^{2} , \text{m/s}^{2}$
D)$ 8\pi m/s^{2} $
Show Answer
Answer:
Correct Answer: C
Solution:
Centripetal acceleration$ =4{{\pi }^{2}}n^{2}r=4{{\pi }^{2}}{{( \frac{1}{2} )}^{2}}\times 2=2{{\pi }^{2}} $
BETA
