Kinematics Question 803
Question: A particle describes a horizontal circle in a conical funnel whose inner surface it’s smooth with speed of 0.5 m/s. What is the height of the plane of circle from vertex of the funnel ? [J&K CET 2005]
Options:
A)0.25 cm
B) 2 cm
C) 4 cm
D) 2.5 cm
Show Answer
Answer:
Correct Answer: D
Solution:
The particle is moving in circular path , $ mg=R\sin \theta $ -(i) $ \ \frac{mv^{2}}{r}=R\cos \theta $ -(ii)
From equation (i) and (ii) we get $ \tan \theta =\frac{rg}{v^{2}} $ but $ \tan \theta =\frac{r}{h} $ $ h=\frac{v^{2}}{g}=\frac{{{(0.5)}^{2}}}{10}=0.025m=2.5cm $
BETA
