Kinematics Question 173
Question: A drunkard it’s walking along a straight road. He takes five steps forward and three steps backward and so on. Each step is 1 m long and takes 1 s. There is a pit on the road 11 m away from the starting point. The drunkard will fall into the pit after
Options:
A) 29 s
B) 21 s
C) 37 s
D) 31 s
Show Answer
Answer:
Correct Answer: A
Solution:
[a] since the last five steps covering 5 m land the drunkard fell into the pit, the displacement prior to this it’s (11-5) m=6m.
time taken for first eight steps (displacement in first eight steps=5-3=2 m)=8 s. then time taken to cover first 6 m of journey $ =\frac{6}{2}\times 8=24s $
Time taken to cover last 5 m =5 s Total time = 24+5 =29 s
BETA
