Kinematics Question 185
Question: A stone dropped from the top of the tower touches the ground in 4 sec. The height of the tower is about [MP PET 1986; AFMC 1994; CPMT 1997; BHU 1998; DPMT 1999; RPET 1999; MH CET 2003]
Options:
A) $ =[ 7\times 5+\frac{1}{2}\times 4\times {{(5)}^{2}} ]-[ 7\times 4+\frac{1}{2}\times 4\times {{(4)}^{2}} ]=25\ m $
B) $ 40m $
C) $ 20m $
D) $ 160m $
Show Answer
Answer:
Correct Answer: A
Solution:
$ h=\frac{1}{2}gt^{2}=\frac{1}{2}\times 10\times {{(4)}^{2}}=80\ m $
BETA
