Kinematics Question 187
Question: A mass m slips along the wall of a semispherical surface of radius R. The velocity at the bottom of the surface it’s [MP PMT 1993]
Options:
A) $ \sqrt{Rg} $
B) $ \sqrt{2Rg} $
C) $ 2\sqrt{\pi Rg} $
D) $ \sqrt{\pi Rg} $
Show Answer
Answer:
Correct Answer: B
Solution:
By applying law of conservation of energy $ mgR=\frac{1}{2}mv^{2}\Rightarrow v=\sqrt{2Rg} $
BETA
