Kinetic Theory Of Gases Question 1

One mole of an ideal monatomic gas requires 210 J heat to raise the temperature by 10 K, when heated at constant volume. If the same gas is heated at constant temperature to raise the temperature by 10 K then heat required is

Options:

A) 238 J

B) 126 J

C) 210 J

D) 350 J

Show Answer

Answer:

Correct Answer: B

Solution:

[b] $ Q _{p}=\mu C _{P}\Delta T $ and $ Q _{v}=\mu C _{v}\Delta T $
$ \Rightarrow \frac{QV}{QP}=\frac{CV}{CP}=\frac{\frac{3}{2}R}{\frac{5}{2}R}=\frac{3}{5} $

$ [ \

Therefore (C_V)_mono=\frac{3}{2}R,\ (C_P)_mono=\frac{5}{2}R\ ] $

$ \Rightarrow QV=\frac{3}{5}\times (\Delta Q)V=\frac{3}{5}\times 210=126J $



Organic Chemistry PYQ

JEE Chemistry Organic Chemistry

Mindmaps Index