Kinetic Theory Of Gases Question 39
Question: The quantity of gas in a closed vessel is halved and the velocities of its molecules are doubled. The final pressure of the gas will be
Options:
A) P
B) 2P
C) P/2
D) 4P
Show Answer
Answer:
Correct Answer: B
Solution:
[b] $ v _{rms}=\sqrt{\frac{3P}{\rho }}=\sqrt{\frac{3PV}{m}}\Rightarrow P=\frac{m,{{(v _{rms})}^{2}}}{3V} $ If P’ be the final pressure then $ \frac{P’}{P}=[ \frac{\frac{\frac{m}{2}{{( 2v _{rms} )}^{2}}}{3V}}{\frac{m{{( v _{rms} )}^{2}}}{3V}} ]=2\Rightarrow P’=2P. $
BETA
