Kinetic Theory Of Gases Question 133
Question: The value of the gas constant (R) calculated from the perfect gas equation is 8.32 joules/gm mole K, whereas its value calculated from the knowledge of $ C _{P} $ and $ C _{V} $ of the gas is 1.98 cal/gm mole K. From this data, the value of J is
Options:
A) $ 4.16\ J/cal $
B) $ 4.18\ J/cal $
C) $ 4.20\ J/cal $
D) $ 4.22\ J/cal $
Show Answer
Answer:
Correct Answer: C
Solution:
[c] We know that $ C _{P}-C _{V}=\frac{R}{J} $
Therefore $ J=\frac{R}{C _{P}-C _{V}} $ $ C _{P}-C _{V}=1.98\ \frac{cal}{gm-mol-K} $ , $ R=8.32\frac{J}{gm-mol-K} $
$ \
Therefore \ J=\frac{8.32}{1.98}=4.20\ J/cal $
BETA
