Kinetic Theory Of Gases Question 137
Question: The average translational energy and the r.m.s. speed of molecules in a sample of oxygen gas at 300 K are $ 6.21\times {{10}^{-21}},J $ and 484 m/s respectively. The corresponding values at 600 K are nearly (assuming ideal gas behaviour)
Options:
A) $ 12.42\times 10^{21},J,\ 968,m/s $
B) $ 8.78\times 10^{21}J,\ 684,m/s $
C) $ 6.21\times 10^{21},J,,968,m/s $
D) $ 12.42\times 10^{21},J,\ 684,m/s $
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Answer:
Correct Answer: D
Solution:
[d] We know that average translational $ K.E. $ of a molecules $ =\frac{3}{2}kT $ At $ 300K, $ average $ K.E.=6.21\times {{10}^{-21}}J $ At $ 600K, $ average $ K.E=2\times (6.21\times {{10}^{-21}}) $ $ =12.42\times {{10}^{-21}}J $ We know that $ v _{rms}=\sqrt{\frac{3kT}{m}} $ At $ 300K, $
$ v _{rms}=484,m/s $ At $ 600K, $
$ {{{v}’} _{rms}}=\sqrt{2}\times 484=684m/s $
BETA
