Kinetic Theory Of Gases Question 139

Question: The average translational kinetic energy of a hydrogen gas molecules at NTP will be [Boltzmannย’s constant $ k _{B}=1.38\times {{10}^{-23}}J/K] $

Options:

A) $ 0.186\times {{10}^{-20}} $ Joule

B) $ 0.372\times {{10}^{-20}} $ Joule

C) $ 0.56\times {{10}^{-20}} $ Joule

D) $ 5.6\times {{10}^{-20}} $ Joule

Show Answer

Answer:

Correct Answer: C

Solution:

[c] $ E _{av}=\frac{f}{2}kT=\frac{3}{2}\times 1.38\times {{10}^{-23}}\times 273 $

$ =0.56\times {{10}^{-20}}J $



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