Kinetic Theory Of Gases Question 149
Question: Two spherical vessels of equal volume are connected by a narrow tube. The apparatus contains an ideal gas at 1 atm and 300 K. Now, if one vessel is immersed in a bath of constant temperature 600K and other in a bath of constant temperature 300K, then common pressure will be
Options:
A) 1 atm
B) 4/5 atm
C) 4/3 atm
D) 3/2 atm
Show Answer
Answer:
Correct Answer: C
Solution:
[c] Initial pressure, $ p _{1}=p _{2}=p _{0}=\frac{nRT _{0}}{V _{0}} $ when $ p _{0}=1 $ atm $ T _{0}=300K. $ Finally, let common pressure is p. So, $ \frac{pV _{0}}{R\times 2T _{0}}=n _{1} $ and $ \frac{pV _{0}}{RT _{0}}=n _{2} $ and $ n _{1}+n _{2}=2n $ $ \frac{pV _{0}}{2RT _{0}}+\frac{pV _{0}}{RT _{0}}=2( \frac{p _{0}V _{0}}{RT _{0}} ) $
$ \Rightarrow $ $ p=\frac{4}{3}p _{0}=\frac{4}{3}atm $
BETA
