Kinetic Theory Of Gases Question 157

Question: Three closed vessels A, B and C are at the same temperature T and contain gases which obey the Maxwellian distribution of velocities. Vessel A contains only $ O _{2},B $ only $ N _{2}, $ and $ O _{2} $ mixture of equal quantities of $ O _{2} $ and $ N _{2} $ . If the average speed of the $ O _{2} $ molecules in vessel A is $ V _{1} $ that of the $ N _{2} $ molecules in vessel B is $ V _{2} $ then the average speed of the $ O _{2} $ molecules in vessel C is (where M is the mass of an oxygen molecule)

Options:

A) $ (V _{1}+V _{2})/2 $

B) $ V _{1} $

C) $ {{(V _{1}V _{2})}^{1/2}} $

D) $ \sqrt{3kT/M} $

Show Answer

Answer:

Correct Answer: B

Solution:

[b] Average speed of gas molecule $ v _{av}=\sqrt{\frac{8kT}{\pi m}} $ . It depends on temperature and molecular mass. So the average speed of oxygen will be same in vessel A and vessel C and that is equal to $ V _{1} $ .