Kinetic Theory Of Gases Question 163

Question: The value of $ C _{p}-C _{v}=1.00R $ for a gas in state A and $ C _{p}-C _{v}=1.06R $ in another state. If $ P _{A} $ and $ P _{B} $ denote the pressure and $ T _{A} $ and $ T _{B} $ denote the temperatures in the two states, respectively, then

Options:

A) $ P _{A}=P _{B},,T _{A}>T _{B} $

B) $ P _{A}>P _{B},,P _{A}=T _{B} $

C) $ P _{A}<P _{B},,P _{A}>P _{B} $

D) $ P _{A}>P _{B},,T _{A}<T _{B} $

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Answer:

Correct Answer: C

Solution:

[c] For state $ A,,C _{p}-C _{v}=R, $ i.e., the gas behaves as ideal gas. For state $ B,,C _{p}-C _{v}=1.06,R(\ne R), $ i.e., the gas does not behave like ideal gas. And we know that at high temperature and at low pressure nature of gas may be ideal. So we can say that $ P _{A}<P _{B} $ and $ T _{A}>T _{B} $