Kinetic Theory Of Gases Question 163

The value of $ C _{p}-C _{v}=R $ for a gas in state A and $ C _{p}-C _{v}=1.06R $ in another state. If $ P _{A} $ and $ P _{B} $ denote the pressure and $ T _{A} $ and $ T _{B} $ denote the temperatures in the two states, respectively, then

Options:

A) $ P _{A}=P _{B},,T _{A}>T _{B} $

B) $ P _{A}>P _{B},,P _{A}=T _{B} $

C) $ P _{A}<P _{B},,P _{A}>P _{B} $

D) $ P _{A}>P _{B},,T _{A}<T _{B} $

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Answer:

Correct Answer: C

Solution:

[c] For state $ A,,C _{p}-C _{v}=R, $ i.e., the gas behaves as ideal gas. For state $ B,,C _{p}-C _{v}=1.06,R(\ne R), $ i.e., the gas does not behave like an ideal gas. And we know that at high temperature and at low pressure the nature of gas may be ideal. So we can say that $ P _{A}<P _{B} $ and $ T _{A}>T _{B} $



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