Kinetic Theory Of Gases Question 164
Question: $ 22,g $ of $ CO _{2} $ at $ 27^{o}C $ is mixed with $ 16,g $ of $ O _{2} $ at $ 37{}^\circ C $ . The temperature of the mixture is
Options:
A) $ 32{}^\circ C $
B) $ 27{}^\circ C $
C) $ 37{}^\circ C $
D) $ 30.5{}^\circ C $
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Answer:
Correct Answer: A
Solution:
[a] Let t is the temperature of mixture. Heat gained by $ CO _{2}= $ Heat lost by $ O _{2} $
$ \Rightarrow $ $ {\mu _{1}}{C _{v _{1}}}\Delta T _{1}={\mu _{2}}{C _{v _{2}}}\Delta T _{2} $
$ \Rightarrow $ $ \frac{22}{44}(3R),(t-27)=\frac{16}{32}( \frac{5}{2}R ),(37-t) $
$ \Rightarrow $ $ 3(t-27),=\frac{5}{2},(37-t) $ By solving, we get $ t=32^{o}C $
BETA
