Kinetic Theory Of Gases Question 2
Energy of all molecules of a monatomic gas having a volume $ V $ and pressure $ p $ is 3/2 $ p $ $ V $ . The total translational kinetic energy of all molecules of a diatomic gas at the same volume and pressure is
Options:
A) $ 1/2,PV $
B) $ 3/2,PV $
C) $ 5/2,PV $
D) $ 3,PV $
Show Answer
Answer:
Correct Answer: B
Solution:
Energy of mol of gas $ =\frac{f}{2}RT=\frac{f}{2}PV $ Where f= degree of freedom Monatomic gases have f=3, diatomic gases have f=5, and they possess different degree of freedom $ \
Therefore E=\frac{3}{2}nRT $
BETA
