Kinetic Theory Of Gases Question 45
Question: A gas mixture consists of molecules of type 1, 2 and 3, with molar masses $ m _{1}>m _{2}>m _{3}.v _{rms} $ and $ \bar{K} $ are the r. m. s. speed and average kinetic energy of the gases. Which of the following is true?
Options:
A) $ (v_rms)_1<(v_rms)_2<(v_rms)_3 $ and $ {(\bar{K})_1}={(\bar{K})_2}={(\bar{K})_3} $
B) $ (v_rms)_1=(v_rms)_2=(v_rms)_3 $ and $ {(\bar{K})_1}={(\bar{K})_2}>{(\bar{K})_3} $
C) $ (v_rms)_1>(v_rms)_2>(v_rms)_3 $ and $ {(\bar{K})_1}<{(\bar{K})_2}>{(\bar{K})_3} $
D) $ (v_rms)_1>(v_rms)_2>(v_rms)_3 $ and $ {(\bar{K})_1}<{(\bar{K})_2}<{(\bar{K})_3} $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ v _{rms}\propto \frac{1}{\sqrt{M}}$
$\Rightarrow (v_rms)_1<(v_rms)_2<(v_rms)_3 $
Also in mixture temperature of each gas will be same, hence kinetic energy also remains same.
BETA
