Kinetic Theory Of Gases Question 48
Three closed vessels A, B and C are at the same temperature T and contain gases which obey the Maxwellian distribution of velocities. Vessel A contains only $ O _{2} $ , B only $ N _{2} $ and C a mixture of equal quantities of $ O _{2} $ and $ N _{2} $ . If the average speed of the $ O _{2} $ molecules in vessel A is that of the $ N _{2} $ molecules in vessel B is $ v _{2}, $ the average speed of the $ O _{2} $ molecules in vessel C is
Options:
A) $ \frac{v _{1}+v _{2}}{2} $
B) $ v _{1} $
C) $ {{( v _{1}.v _{2} )}^{\frac{1}{2}}} $
D) $ \sqrt{\frac{3kT}{M}} $
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Answer:
Correct Answer: B
Solution:
All three vessels are at same temperature. According to Maxwell’s distribution of speed, average speed of molecules of a gas $ v\propto \sqrt{\frac{1}{T}} $ . $ \
Therefore $ The velocity of oxygen molecules will be same in A as well as C where M is the mass of an oxygen molecule.
BETA
