Kinetic Theory Of Gases Question 58
Question: A perfect gas at $ 27{}^\circ C $ is heated at constant pressure so as to double its volume. The final temperature of the gas will be, close to
Options:
A) (a) $ 327{}^\circ C $
B) $ 200{}^\circ C $
C) $ 54{}^\circ C $
D) $ 300{}^\circ C $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] Given, $ V _{1}=V,V _{2}=2V $
$ T _{1}=27{}^\circ +273=300K\text{ so, }T _{2}=? $ From charle’s law $ \frac{V _{1}}{T _{1}}=\frac{V _{2}}{T _{2}}\text{ or, }\frac{V}{300}=\frac{2V}{T _{2}} $ ( $ \
Therefore $ Pressure is constant)
$ \
Therefore ~,T _{2}=600K=600-273=327{}^\circ C $
BETA
