Kinetic Theory Of Gases Question 63

Question: The mean free path of molecules of a gas, (radius

Options:

A) $ r^{3} $

B) $ r^{2} $

C) $ r $

D) $ \sqrt{r} $

Show Answer

Answer:

Correct Answer: B

Solution:

[b] Mean free path $ {\lambda _{m}}=\frac{1}{\sqrt{2}\pi d^{2}n} $ Where d = diameter of molecule and $ d=2r $
$ \

Therefore {\lambda _{m}}\propto \frac{1}{r^{2}} $



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