Kinetic Theory Of Gases Question 63
Question: The mean free path of molecules of a gas, (radius
Options:
A) $ r^{3} $
B) $ r^{2} $
C) $ r $
D) $ \sqrt{r} $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] Mean free path $ {\lambda _{m}}=\frac{1}{\sqrt{2}\pi d^{2}n} $ Where d = diameter of molecule and $ d=2r $
$ \
Therefore {\lambda _{m}}\propto \frac{1}{r^{2}} $
BETA
