Kinetic Theory Of Gases Question 34
Question: The temperature of an ideal gas is increased from 120 K to 480 K. If at 120 K the root-mean-square velocity of the gas molecules is v, at 480 K it becomes
Options:
A) 4v
B) 2v
C) v/2
D) v/4
Show Answer
Answer:
Correct Answer: B
Solution:
[b] $ \frac{(V_rms)_1}{(V_rms)_2} $
=$\sqrt{\frac{T _{1}}{T _{2}}}$
$\Rightarrow \frac{V}{{{( V _{rms} )}^{2}}}=\sqrt{\frac{120}{480}} $
$ \Rightarrow \frac{V}{( V _{rms} ) _{2}}=\frac{1}{2}$
$\Rightarrow {{( V _{rms} )} _{2}}=2V $
BETA
