Kinetic Theory Of Gases Question 73
Question: A polyatomic gas with n degrees of freedom has a mean energy per molecule given by
Options:
A) $ \frac{nkT}{N} $
B) $ \frac{nkT}{2N} $
C) $ \frac{nkT}{2} $
D) $ \frac{3kT}{2} $
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Answer:
Correct Answer: C
Solution:
[c] According to law of equipartition of energy, the energy per degree of freedom is $ \frac{1}{2}kT. $ For a polyatomic gas with n degrees of freedom, the mean energy per molecule $ =\frac{1}{2}nkT $
BETA
